Import Question JSON

Current Question (ID: 16679)

Question:
$\text{The internal resistance of a } 2.1 \text{ V cell which gives a current of } 0.2 \text{ A through a resistance of } 10 \ \Omega \text{ is:}$
Options:
  • 1. $0.5 \ \Omega$
  • 2. $0.8 \ \Omega$
  • 3. $1.0 \ \Omega$
  • 4. $0.2 \ \Omega$
Solution:
$\text{Hint: } I = \frac{E}{R+r}$ $\text{Step: Find the internal resistance of the cell.}$ $\text{Let the internal resistance of the cell is } r.$ $\text{The total resistance of the circuit } = R + r = 10 + r$ $E = 2.1 \text{ V}$ $\text{The current in the circuit is given by:}$ $I = \frac{E}{R+r}$ $\Rightarrow 0.2 = \frac{2.1}{10+r}$ $\Rightarrow r = 0.5 \ \Omega$ $\text{Hence, option (1) is the correct answer.}$

Import JSON File

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Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}