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Current Question (ID: 16723)

Question:
$\text{The potential difference across } 8 \, \Omega \text{ resistance is } 48 \, \text{V as shown in the figure below.}$ $\text{The value of potential difference across } X \text{ and } Y \text{ points will be:}$
Options:
  • 1. $160 \, \text{V}$
  • 2. $128 \, \text{V}$
  • 3. $80 \, \text{V}$
  • 4. $62 \, \text{V}$
Solution:
$\text{Hint: } V = IR$ $\text{Step: Find the value of potential difference across } X \text{ and } Y \text{ points.}$ $\text{The given circuit can be redrawn as follows:}$ $\text{The resistance between } A \text{ and } B \text{ is given by;} \ R = \frac{24 \times 8}{32} = 6 \, \Omega$ $\text{The current between } A \text{ and } B = \text{The current between } X \text{ and } Y$ $\Rightarrow i = \frac{48}{6} = 8 \, \text{A}$ $\text{The resistance between } X \text{ and } Y \text{ is given by;} \ R = (3 + 10 + 6 + 1) = 20 \, \Omega$ $\text{The potential difference between } X \text{ and } Y \text{ is given by;} \ \Delta V = 8 \times 20 = 160 \, \text{V}$ $\text{Hence, option (1) is the correct answer.}$

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Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}