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Current Question (ID: 16724)

Question:
$\text{In the circuit shown in the figure below, if the potential at point } A \text{ is taken to be zero, the potential at point } B \text{ will be:}$
Options:
  • 1. $+1 \text{ V}$
  • 2. $-1 \text{ V}$
  • 3. $+2 \text{ V}$
  • 4. $-2 \text{ V}$
Solution:
$\text{Hint: Apply KVL.}$ $\text{Step: Find the potential at point } B.$ $\text{By KVL along path ACDB:}$ $V_A + 1 + (1)(2) - 2 = V_B$ $0 + 1 = V_B$ $\Rightarrow V_B = 1 \text{ volt}$

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Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}