Import Question JSON

Current Question (ID: 16731)

Question:
$\text{What is the equivalent resistance between points } a \text{ and } b, \text{ if the value of each resistance is } R?$
Options:
  • 1. $7R$
  • 2. $5R$
  • 3. $4R$
  • 4. $3R$
Solution:
$\text{Hint: Apply the condition of the Wheatstone bridge.}$ $\text{Step 1: Find the net resistance of the Wheatstone bridge.}$ $\frac{1}{R_1} = \frac{1}{2R} + \frac{1}{2R} = \frac{2}{2R}$ $R_1 = R$ $\text{Step 2: Find the net resistance of the circuit.}$ $R_{\text{net}} = R + R + R = 3R$

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Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}