Import Question JSON

Current Question (ID: 16781)

Question:

$\text{Given below are two statements:}$ $\text{Statement I:}$ \text{The electric force changes the speed of the charged particle and hence changes its kinetic energy: whereas the magnetic force does not change the kinetic energy of the charged particle.}$ $\text{Statement II:}$ \text{The electric force accelerates the positively charged particle perpendicular to the direction of the electric field. The magnetic force accelerates the moving charged particle along the direction of the magnetic field.}$

Options:

1. $\text{Both Statement I and Statement II are correct.}$
2. $\text{Both Statement I and Statement II are incorrect.}$
3. $\text{Statement I is correct and Statement II is incorrect.}$
4. $\text{Statement I is incorrect and Statement II is correct.}$

Solution:

$\text{Hint: The electric force acts along the direction of an electric field.}$ $\text{Explanation: An electric field can change speed and kinetic energy but the magnetic field cannot change speed and kinetic energy, because the magnetic force always accelerates the charged particle perpendicular to the magnetic field while the electric field accelerates the charged particle along the line of the electric field.}$ $\text{Hence, option (3) is the correct answer.}$

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}