Import Question JSON

Current Question (ID: 16824)

Question:

$\text{What is the magnetic moment of the following current loop?}$ $\begin{array}{c} \text{3 m} \\ \text{90}^\circ \\ \end{array}$ $\begin{array}{c} \text{2 A} \\ \text{4 m} \\ \end{array}$

Options:

1. $24 \ \text{Am}^2$
2. $12 \ \text{Am}^2$
3. $6 \ \text{Am}^2$
4. $\text{zero}$

Solution:

$\text{Hint: Magnetic moment of the loop is given as } \vec{\text{M}} = \text{I} \vec{\text{A}}.$ $\text{Step 1: Calculate the magnetic moment.}$ $\vec{\text{M}} = \text{I} \vec{\text{A}}$ $= 2 \times \frac{1}{2} \times 3 \times 4$ $= 12 \ \text{Am}^2$

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}