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Current Question (ID: 16838)

Question:

$\text{A closed-loop (of any shape) carrying current lies in the } x-y \text{ plane.}$ $\text{What happens when a uniform magnetic field } B \text{ is present in the region such that the loop experiences zero force?}$

Options:

1. $B \text{ acts along the } x\text{-axis}$
2. $B \text{ acts along the } y\text{-axis}$
3. $B \text{ acts along the } z\text{-axis}$
4. $B \text{ can act along any of the above direction for the net force to be zero}$

Solution:

$\text{(4)}$ $\text{when the close loop is placed in a uniform magnetic field, then the net force acting on the loop is always zero.}$

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Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}