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Current Question (ID: 16846)

Question:
$\text{What happens when the number of turns in a galvanometer is doubled?}$
Options:
  • 1. $\text{The voltage sensitivity becomes double.}$
  • 2. $\text{The current sensitivity becomes double.}$
  • 3. $\text{The voltage sensitivity becomes half.}$
  • 4. $\text{The current sensitivity remains the same.}$
Solution:
$\text{Hint: Recall the moving coil galvanometer.}$ $\text{Step 1: Find the current sensitivity.}$ $\text{The current sensitivity is given by:}$ $k \theta = \frac{NiAB}{k}$ $\frac{\theta}{i} = \frac{NAB}{k}$ $\text{The current sensitivity on doubling the number of turns, current sensitivity is also doubled.}$ $\text{Step 2: Find the voltage sensitivity.}$ $\text{As voltage sensitivity is given by:}$ $\frac{\theta}{V} = \frac{NAB}{kR}$ $\text{So, on doubling the number of turns, the resistance of the coil also gets doubled and hence the voltage sensitivity remains the same.}$ $\text{Hence, option (2) is the correct answer.}$

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Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}