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Current Question (ID: 16851)

Question:
$\text{A galvanometer with a resistance of } 36 \, \Omega \text{ is changed into an ammeter by using a shunt of } 4 \, \Omega. \text{ The fraction } f_0 \text{ of total current passing through the galvanometer will be:}$
Options:
  • 1. $\frac{1}{40}$
  • 2. $\frac{1}{4}$
  • 3. $\frac{1}{140}$
  • 4. $\frac{1}{10}$
Solution:
$\frac{i_g}{i} = \frac{S}{G+S} = \frac{4}{36+4} = \frac{4}{40} = \frac{1}{10}$

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Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}