Import Question JSON

Current Question (ID: 16863)

Question:
$\text{Which of the following is the correct representation of magnetic field lines?}$
Options:
  • 1. $(g), (c)$
  • 2. $(d), (f)$
  • 3. $(a), (b)$
  • 4. $(c), (e)$
Solution:
$\text{Hint: Recall the properties of magnetic field lines.}$ $\text{Explanation: Analyze the diagrams.}$ $\text{(a) Wrong, because magnetic lines of force never emanate from a single point as shown.}$ $\text{(b) Wrong, because magnetic field lines do not cross one another.}$ $\text{(c) Correct, magnetic lines of force are confined within a toroid. Field lines form closed loops as each loop encloses a region across which a current passes.}$ $\text{(d) Wrong, field lines cannot be completely straight. The lines should curve out at the edges and form closed loops.}$ $\text{(e) Correct, around both, the N-pole and S-pole, the net flux of the field is zero.}$ $\text{(f) Wrong, these lines cannot represent a magnetic field because all the field lines cannot emanate from the upper shaded (plate).}$ $\text{(g) Wrong, magnetic field lines between two poles cannot be precisely straight at the ends. Some deviation of lines is inevitable, otherwise, Ampere's law is violated.}$ $\text{Hence, option (4) is the correct answer.}$

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Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}