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Current Question (ID: 16905)

Question:
$\text{The magnetization of a piece of iron or steel:}$
Options:
  • 1. $\text{depends on the strength of the magnetizing field.}$
  • 2. $\text{depends on external conditions such as temperature.}$
  • 3. $\text{cannot be done beyond the saturation point.}$
  • 4. $\text{all of these.}$
Solution:
$\text{Hint: } I = \chi H$ $\text{Explanation: The magnetization of a piece of iron or steel depends on the strength of the magnetizing field.}$ $I = \chi H$ $\chi \text{ depends on the temperature of ferromagnetic and paramagnetic materials.}$ $\text{The magnetization cannot be done beyond the saturation point.}$ $\text{The magnetization of a material increases with the strength of the applied magnetizing field until it reaches saturation.}$ $\text{Magnetization decreases with increasing temperature, and materials can lose their magnetic properties above a certain temperature, known as the Curie temperature.}$ $\text{Once the material reaches its saturation magnetization, increasing the magnetizing field further will not increase the magnetization anymore.}$ $\text{Therefore, all of these are correct.}$ $\text{Hence, option (4) is the correct answer.}$

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Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}