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Current Question (ID: 16907)

Question:

$\text{There are two materials } A \text{ and } B. \text{ The material } B \text{ have high coercivity and } A \text{ have low coercivity. The hysteresis loop area of material } A \text{ is lesser than the material } B. \text{ Then:}$

Options:

1. $\text{material } A \text{ is preferred for making electromagnets.}$
2. $\text{material } B \text{ is preferred for making permanent magnets.}$
3. $\text{material } A \text{ is preferred for using electric generators and transformers.}$
4. $\text{all of these.}$

Solution:

$\text{Hint: The materials suitable for making electromagnets should have high retentivity and low coercivity.}$ $\text{Explanation: The materials suitable for making electromagnets should have high retentivity and low coercivity. Therefore material } A \text{ is preferred for making electromagnets. When the material has high coercivity it does not lose its magnetization easily. Therefore material } B \text{ is preferred for making permanent magnets. If the hysteresis is narrow, then the energy loss during magnetization and demagnetization will be very less, therefore material } A \text{ is preferred for using electric generators and transformers.}$

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Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}