Import Question JSON

Current Question (ID: 16957)

Question:

$\text{An aluminium ring } B \text{ faces an electromagnet } A. \text{ If the current } I \text{ through } A \text{ can be altered, then:}$

Options:

1. $\text{whether } I \text{ increases or decreases, } B \text{ will not experience any force.}$
2. $\text{if } I \text{ decreases, } A \text{ will repel } B.$
3. $\text{if } I \text{ increases, } A \text{ will attract } B.$
4. $\text{if } I \text{ increases, } A \text{ will repel } B.$

Solution:

$\text{Hint: When } I \text{ increases, the induced current in the ring opposes the electromagnet's field, causing a repulsive force.}$ $\text{Explanation: When the current } I \text{ through electromagnet } A \text{ increases, the magnetic field around } A \text{ strengthens. According to Lenz's Law, the induced current in the aluminum ring } B \text{ will flow in a direction that opposes the increase in magnetic flux. This creates a magnetic field in } B \text{ that opposes the magnetic field of } A, \text{ resulting in a repulsive force between them.}$ $\text{If } I \text{ decreases, the magnetic flux decreases, and } B \text{ will be induced to generate a magnetic field in the same direction as } A, \text{ causing an attractive force.}$ $\text{If the current through } A \text{ increases, flux linked with coil } B \text{ increases, hence anticlockwise current is induced in the coil } B. \text{ As shown in the figure both currents produce the repulsive effect.}$ $\text{Hence, option (4) is the correct answer.}$

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}