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Current Question (ID: 17332)

Question:
$\text{The diagram shows a capacitor } C \text{ and a resistor } R \text{ connected in series to an AC source. } V_1 \text{ and } V_2 \text{ are voltmeters and } A \text{ is an ammeter.}$ $\text{Consider now the following statements}$ $\text{I. Readings in } A \text{ and } V_2 \text{ are always in phase}$ $\text{II. Reading in } V_1 \text{ is ahead in phase with reading in } V_2$ $\text{III. Readings in } A \text{ and } V_1 \text{ are always in phase}$ $\text{Which of these statements is/are correct?}$
Options:
  • 1. $\text{I only}$
  • 2. $\text{II only}$
  • 3. $\text{I and II only}$
  • 4. $\text{II and III only}$
Solution:
$\text{In } RC \text{ series circuit voltage across the resistance leads the voltage across the capacitor by } \frac{\pi}{2} \text{ and the current in the circuit is always in phase with the voltage across resistance.}$

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Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}