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Current Question (ID: 17375)

Question:
$\text{The primary winding of a transformer has 500 turns whereas its secondary has 5000 turns. The primary is connected to an AC supply of 20 V, 50 Hz. What will be the output of the secondary transformer?}$
Options:
  • 1. $200 \text{ V, 50 Hz}$
  • 2. $2 \text{ V, 50 Hz}$
  • 3. $200 \text{ V, 500 Hz}$
  • 4. $2 \text{ V, 5 Hz}$
Solution:
$\frac{V_s}{V_p} = \frac{N_s}{N_p} \Rightarrow \frac{V_s}{20} = \frac{5000}{500}$ $\Rightarrow V_s = 200 \text{ V}$ $\text{Frequency remains unchanged.}$

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Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}