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Current Question (ID: 17393)

Question:

$\text{A capacitor is made of two circular plates each of radius 12 cm and separated by 5.0 cm. The capacitor being charged by an external source. The charging current is constant and equal to 0.15 A. The displacement current across the plates is:}$ $1.\ 0$ $2.\ 0.14\ \text{A}$ $3.\ 0.16\ \text{A}$ $4.\ 0.15\ \text{A}$

Options:

1. $0$
2. $0.14\ \text{A}$
3. $0.16\ \text{A}$
4. $0.15\ \text{A}$

Solution:

$\text{Hint: The current conduction current is equal to the displacement current.}$ $\text{Explanation: To maintain the continuity of current conduction current is equal to the displacement current.}$ $\text{The displacement current across the plate is the same as the conduction current. Therefore, the displacement current } i_d = 0.15\ \text{A}. \text{ Hence, option (4) is the correct answer.}$

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}