Import Question JSON

Current Question (ID: 17397)

Question:

$\text{Given below are two statements:}$ $\text{Assertion (A):}$ \text{Displacement current goes through the gap between the plates of a capacitor when the charge of the capacitor does not change}$ $\text{Reason (R):}$ \text{The displacement current arises in the region in which the electric field and hence the electric flux does not change with time.}$

Options:

1. $\text{Both (A) and (R) are True and (R) is the correct explanation of (A).}$
2. $\text{Both (A) and (R) are True but (R) is not the correct explanation of (A).}$
3. $\text{(A) is True but (R) is False.}$
4. $\text{Both (A) and (R) are False.}$

Solution:

$\text{Hint: } i_d = \varepsilon_0 \frac{d\phi_E}{dt}$ $\text{Explanation: The displacement current arises only when there is a time-varying electric field, which corresponds to a changing charge on the plates of the capacitor. If the charge on the capacitor does not change, there is no changing electric field, and hence no displacement current. So, (A) is false. Displacement current arises in a region where the electric field or electric flux changes with time, not in a region where it remains constant. So, (R) is false. Therefore, both (A) and (R) are False. Hence, option (4) is the correct answer.}$

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}