Import Question JSON

Current Question (ID: 17451)

Question:
$\text{The condition under which a microwave oven heats up a food item containing water molecules most efficiently is:}$
Options:
  • 1. $\text{the frequency of the microwave must match the resonant frequency of the water molecules.}$
  • 2. $\text{the frequency of the microwave has no relation to the natural frequency of water molecules.}$
  • 3. $\text{microwave are heatwaves, so always produce heating.}$
  • 4. $\text{infrared waves produce heating in a microwave oven.}$
Solution:
$\text{The frequency of the microwaves must match the resonant frequency of the water molecules.}$ $\text{According to the NCERT textbook the correct option is (1) and for the NEET exam, NCERT text is to be preferred while marking the answer. So, choose option (1) in exam.}$ $\text{But for your knowledge, please note that option (2) is actually correct here.}$ $\text{Microwave ovens operate at a frequency of 2.45 GHz (2.45 \times 10^9 \text{ Hz}) and this is NOT the resonant frequency of a water molecule. This frequency is much lower than the diatomic molecule resonant frequencies mentioned earlier. If 2.45 GHz were the resonant frequency of water molecules the microwaves would all be absorbed in the surface layer of a substance (liquid water or food) and so the interior of the food would not get cooked at all.}$

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}