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Current Question (ID: 17455)

Question:
$\text{Light is a kind of wave. The wavelength of visible light ranges from about } 4000 \, \text{\AA} \text{ to } 7000 \, \text{\AA}. \text{ Which of the following statements is false?}$
Options:
  • 1. $\text{Ultraviolet light has a wavelength shorter than } 4000 \, \text{\AA}.$
  • 2. $\text{Infrared light has a wavelength longer than } 7000 \, \text{\AA}.$
  • 3. $\text{Red light has a wavelength near about } 7000 \, \text{\AA}.$
  • 4. $\text{Violet light has a wavelength near about } 7000 \, \text{\AA}.$
Solution:
$\text{Hint: Violet light has a shorter wavelength, around } 4000 \, \text{\AA}, \text{ not near } 7000 \, \text{\AA}.$ $\text{Explanation: The wavelength of visible light ranges from } 4000 \, \text{\AA} \text{ (angstroms) to } 7000 \, \text{\AA}. \text{ Let's examine each statement:}$ $\text{Ultraviolet light has a wavelength shorter than } 4000 \, \text{\AA}. \text{ This is true.}$ $\text{Ultraviolet light has wavelengths shorter than those of visible light, typically ranging from } 10 \, \text{nm to } 400 \, \text{nm} \,(1000 \, \text{\AA} \text{ to } 4000 \, \text{\AA}).$ $\text{Infrared light has a wavelength longer than } 7000 \, \text{\AA}. \text{ This is true.}$ $\text{Infrared light has wavelengths longer than visible light, typically ranging from about } 7000 \, \text{\AA} \,(0.7 \, \mu \text{m}) \text{ to } 1 \, \text{mm}.$ $\text{Red light has a wavelength near about } 7000 \, \text{\AA}. \text{ This is true.}$ $\text{Red light has a wavelength close to } 7000 \, \text{\AA} \,(\text{around } 6200 \, \text{to } 7500 \, \text{\AA}).$ $\text{Violet light has a wavelength near about } 7000 \, \text{\AA}. \text{ This is false.}$ $\text{Violet light has a shorter wavelength, typically ranging from } 3800 \, \text{\AA} \text{ to } 4500 \, \text{\AA}, \text{ not near } 7000 \, \text{\AA}.$ $\text{Hence, option (4) is the correct answer.}$

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Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}