Import Question JSON

Current Question (ID: 17456)

Question:
$\text{The EM wave with the shortest wavelength among the following is:}$
Options:
  • 1. $\text{Ultraviolet rays}$
  • 2. $X\text{-rays}$
  • 3. $\text{Gamma-rays}$
  • 4. $\text{Microwaves}$
Solution:
$\text{Hint: Recall the order of the electromagnetic spectrum.}$ $\text{Explanation: Electromagnetic (EM) waves cover a wide range of wavelengths, from very long (like radio waves) to very short (like gamma rays).}$ $\text{The different types of EM waves are categorized based on their wavelength and frequency.}$ $\text{Ultraviolet rays (UV rays): These have wavelengths in the range of 10 nm to 400 nm.}$ $X\text{-rays: X-rays have wavelengths between 0.01 nm and 10 nm.}$ $\text{Gamma-rays: These have the shortest wavelengths, typically less than 0.01 nm, and can go down to picometer (pm) or even smaller wavelengths.}$ $\text{Gamma rays are produced by nuclear reactions and are highly energetic.}$ $\text{Microwaves: These have wavelengths ranging from 1 mm, to 30 cm, which are much longer than UV rays, X-rays, and gamma rays.}$ $\text{Therefore, gamma rays have the shortest wavelengths in the electromagnetic spectrum and the highest energy, which is why they are classified as the most penetrating and dangerous form of electromagnetic radiation.}$ $\text{Hence, option (3) is the correct answer.}$

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}