Import Question JSON

Current Question (ID: 17462)

Question:

$\text{Which of the following statements about electromagnetic waves is/are correct:}$ $\text{A. } \text{X-rays in a vacuum travel faster than light waves in a vacuum.}$ $\text{B. The energy of a } \text{X-ray photon is greater than that of a light photon.}$ $\text{C. Light can be polarised but } \text{X-rays cannot.}$

Options:

1. $\text{A and B only}$
2. $\text{B and C only}$
3. $\text{A, B, and C only}$
4. $\text{B only}$

Solution:

$\text{Hint: The energy of a ray photon is greater than that of a light photon}$ $\text{Explanation:}$ $\text{Statement I: X-rays, in a vacuum travel faster than light waves in a vacuum}$ $\text{This statement is incorrect. In a vacuum, all electromagnetic waves, including X-rays and light waves, travel at the speed of light, which is approximately } 3 \times 10^8 \text{ m/s}$ $\text{Statement II: The energy of an X-ray photon is greater than that of a light photon}$ $\text{This statement is correct. X-rays have higher energy photons compared to visible light photons. This is why X-rays are used in medical imaging and other applications that require higher-energy electromagnetic radiation}$ $\text{Statement III: Light can be polarized but X-rays cannot}$ $\text{This statement is incorrect. Both light and X-rays can be polarized. Polarization is a property of transverse waves, including electromagnetic waves, where the electric field oscillates in a specific direction.}$ $\text{Hence, option (4) is the correct answer.}$

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}