Import Question JSON

Current Question (ID: 17471)

Question:
$\text{A point source of light } B \text{ is placed at a distance } L \text{ in front of the centre of a mirror of width } d \text{ hung vertically on a wall. A man } (A) \text{ walks in front of the mirror along a line parallel to the mirror at a distance } 2L \text{ from it as shown. The greatest distance over which he can see the image of the light source in the mirror is:}$
Options:
  • 1. $\frac{d}{2}$
  • 2. $d$
  • 3. $2d$
  • 4. $3d$
Solution:
$\text{According to the following ray diagram } HI = AB = d \text{ and } DS = CD = \frac{d}{2}$ $\therefore AH = 2AD \Rightarrow GH = 2CD = \frac{2d}{2} = d$ $\text{Similarly, } IJ = d.$ $\text{So, } GJ = GH + HI + IJ = d + d + d = 3d$

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Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}