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Current Question (ID: 17478)

Question:

$\text{When a concave mirror of focal length } f \text{ is immersed in water, its focal length becomes } f', \text{ then:}$

Options:

1. $f' = f$
2. $f' < f$
3. $f' > f$
4. $\text{The information is insufficient to predict}$

Solution:

$\text{Hint: The focal length is independent of the medium.}$ $\text{Explanation: We know that the law of reflection doesn't depend on the refractive index of the medium.}$ $\text{So, when a concave mirror of focal length } (f) \text{ is immersed in water then, the focal length of the mirror in water remains constant.}$ $\text{The focal length of a concave mirror depends only on its radius of curvature and the nature of the mirror's surface, not on the medium in which it is placed.}$ $\text{When a concave mirror is immersed in water, its focal length remains unchanged because the mirror's properties are based on reflection, not refraction.}$ $\text{Since immersing the mirror in water does not change its radius of curvature or reflective properties, the focal length } f' \text{ remains the same as } f.$ $\text{Therefore, } f' = f.$ $\text{Hence, option (1) is the correct answer.}$

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}