Import Question JSON

Current Question (ID: 17502)

Question:

$\text{In total internal reflection when the angle of incidence is equal to the critical angle for the pair of media in contact, what will be the angle of refraction?}$

Options:

1. $90^\circ$
2. $180^\circ$
3. $0^\circ$
4. $\text{equal to the angle of incidence}$

Solution:

$\text{In total internal reflection, when the angle of incidence is equal to the critical angle, the refracted ray grazes along the boundary between the two media.}$ $\text{This means the angle of refraction is } 90^\circ, \text{ as the refracted ray is parallel to the interface of the two media.}$ $\text{The critical angle is defined as the angle of incidence at which the angle of refraction becomes } 90^\circ.$ $\text{At } i = i_c, \text{ the refracted ray grazes with the surface. So the angle of refraction is } 90^\circ.$ $\text{Therefore, the angle of refraction is } 90^\circ.$ $\text{Hence, option (1) is the correct answer.}$

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}