Import Question JSON

Current Question (ID: 17589)

Question:

$\text{The length of an astronomical telescope adjusted for parallel light is } 90 \text{ cm.}$ $\text{If the magnifying power of the telescope is } 17, \text{ then the focal length of eyepiece and objective are respectively:}$

Options:

1. $10 \text{ cm and } 80 \text{ cm}$
2. $85 \text{ cm and } 5 \text{ cm}$
3. $70 \text{ cm and } 20 \text{ cm}$
4. $5 \text{ cm and } 85 \text{ cm}$

Solution:

$\text{(4)}$ $M = \frac{f_o}{f_e} = 17$ $L = f_o + f_e = 90 \text{ cm}$ $\Rightarrow 17f_e + f_e = 90 \text{ cm}$ $\Rightarrow f_e = 5 \text{ cm}$ $\therefore f_o = 85 \text{ cm}$

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}