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Current Question (ID: 17600)

Question:

$\text{If Compound A (C}_4\text{H}_8\text{) is treated with H}_2\text{O/H}_2\text{SO}_4\text{ and forms an optically inactive C}_4\text{H}_{10}\text{O, what is the structure of A?}$

Options:

1. $\text{CH}_3\text{CH}_2\text{CH} = \text{CH}_2$
2. $\text{CH}_3\text{CH} = \text{CHCH}_3$
3. $(\text{CH}_3)_2\text{C} = \text{CH}_2$
4. $\square$

Solution:

$\text{Hint: Molecule containing chiral carbon is an optically active compound}$ $\text{When alkene reacts with water in the presence of sulphuric acid then alcohol is obtained as a product.}$ $\text{CH}_3\text{CH}_2\text{CH} = \text{CH}_2, \text{CH}_3\text{CH} = \text{CHCH}_3 \text{ and } (\text{CH}_3)_2\text{C} = \text{CH}_2 \text{ all will give alcohol as a product.}$ $\text{The option third alkene will give optically inactive alcohol as a product.}$ $\text{The reaction is as follows:}$ $\text{Alkene CH}_3\text{CH}_2\text{CH} = \text{CH}_2 \text{ and CH}_3\text{CH} = \text{CHCH}_3 \text{ will give optically active alcohol. So it cannot be the answer}$

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Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}