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Current Question (ID: 17601)

Question:
$\text{A compound having the shortest carbon-carbon bond length among the following is:}$ $\text{1. Benzene}$ $\text{2. Ethene}$ $\text{3. Ethyne}$ $\text{4. Ethane}$
Options:
  • 1. $\text{Benzene}$
  • 2. $\text{Ethene}$
  • 3. $\text{Ethyne}$
  • 4. $\text{Ethane}$
Solution:
$\text{Hint: Bond order is inversely proportional to bond length.}$ $\text{The structure of benzene, ethene, ethyne and ethane are as follows:}$ $\text{As bond order increases the carbon-carbon bond length decreases.}$ $\text{Among the benzene, ethene, ethyne and ethane, ethyne}$ $\text{has a triple bond hence it has the shortest bond length.}$ $\text{Ethane has a single bond, hence, it has the longest carbon-carbon bond.}$ $\text{The value of carbon-carbon bond length in the given compound is as follows:}$ $\text{Benzene = 134 pm and 154 pm}$ $\text{Ethene = 134 pm}$ $\text{Ethyne = 120 pm}$ $\text{Ethane = 154 pm}$

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Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}