Import Question JSON

Current Question (ID: 17602)

Question:

$\text{A compound having the highest boiling point among the following is -}$

Options:

1. $\text{Iso-octane}$
2. $\text{n-Octane}$
3. $2,2,3,3\text{-Tetramethyl butane}$
4. $\text{n-Butane}$

Solution:

$\text{Boiling point of hydrocarbon directly proportional to the number of carbon atoms}$ $\text{The higher the number of C-atoms, the higher is the boiling point that is, n-hexane.}$ $\text{This is due to the fact that the intermolecular van der Waals forces increase with the increase in the molecular size or the surface area of the molecule.}$ $\text{With the increase in the number of branched chains, the molecule attains the shape of a sphere.}$ $\text{This results in a smaller area of contact and therefore weak intermolecular forces between spherical molecules, which are overcome at relatively lower temperatures.}$ $\text{So, with an increase in branching the boiling point decreases.}$ $\text{n-octane and 2,2,3,3-tetramethyl butane both contain eight carbons but n-octane has a straight-chain}$ $\text{while 2,2,3,3-tetramethyl butane has a branched chain.}$ $\text{2,2,4-Trimethylpentane is iso-octane.}$ $\text{The correct answer is n-Octane.}$

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}