Import Question JSON

Current Question (ID: 17606)

Question:
$\text{Among the two isomers given above, the reason behind higher boiling point of one isomer as compared to the order is:}$
Options:
  • 1. $\text{Cis - less polar than trans}$
  • 2. $\text{Trans - more polar than cis}$
  • 3. $\text{Cis - more intermolecular forces}$
  • 4. $\text{Trans - more dipole-dipole interactions}$
Solution:
$\text{Hint: The boiling point depends on the force of interaction between the molecules.}$ $\text{Step 1:}$ $\text{Geometrical isomers of Pent-2-ene are given below:}$ $\text{Step 2:}$ $\text{The dipole moment of cis-compound is a sum of the dipole moments of}$ \ C - \text{CH}_3 \ \text{and} \ C - \text{CH}_2\text{CH}_3 \ \text{bonds acting in the same direction.}$ $\text{The dipole moment of trans-compound is the resultant of the dipole moments}$ \ C - \text{CH}_3 \ \text{and} \ C - \text{CH}_2\text{CH}_3 \ \text{of bonds acting in opposite directions.}$ $\text{Hence, cis-isomer is more polar than trans-isomer. The higher the polarity, the greater is the intermolecular dipole-dipole interaction and the higher will be the boiling point. Hence, cis-isomer will have a higher boiling point than trans-isomer.}$

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}