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Current Question (ID: 17608)

Question:
$\text{CH}_3\text{Cl} \ \& \ \text{C}_2\text{H}_5\text{Cl} \ \text{undergoes Wurtz reaction to give-}$
Options:
  • 1. $\text{Propane + Ethane}$
  • 2. $\text{Propane}$
  • 3. $\text{Propane + Ethane + Butane}$
  • 4. $\text{Propane + Butane}$
Solution:
$\text{Hint: In Wurtz reaction, different alkyl halide gives different products}$ $\text{When two different alkyl halides react with each other in the presence of sodium}$ $\text{then multiple products are obtained as products. The reaction is as follows:}$ $\text{(1) CH}_3\text{Cl} + 2 \text{Na} + \text{Cl} - \text{CH}_3 \rightarrow \text{CH}_3 - \text{CH}_3 \ \text{(Ethane)}$ $\text{(2) CH}_3\text{Cl} + 2 \text{Na} + \text{Cl} - \text{CH}_2 - \text{CH}_3 \rightarrow \text{CH}_3 - \text{CH}_2 - \text{CH}_3 \ \text{(Propane)}$ $\text{(3) CH}_3 - \text{CH}_2\text{Cl} + 2 \text{Na} + \text{Cl} - \text{CH}_2 - \text{CH}_3 \rightarrow \text{CH}_3 - \text{CH}_2 - \text{CH}_2 - \text{CH}_3 \ \text{(Butane)}$ $\text{Wurtz reaction gives a mixture of hydrocarbons, which cannot be separated easily.}$

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Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}