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Current Question (ID: 17621)

Question:

$\text{The most acidic compound among the following is-}$ $1.\ \text{CH}_3 - \text{CH}_3$ $2.\ \text{CH}_3 - \text{C} \equiv \text{CH}$ $3.\ \text{CH}_2 = \text{CH}_2$ $4.\ \text{CH}_3\text{C} \equiv \text{C} - \text{CH}_3$

Options:

1. $\text{CH}_3 - \text{CH}_3$
2. $\text{CH}_3 - \text{C} \equiv \text{CH}$
3. $\text{CH}_2 = \text{CH}_2$
4. $\text{CH}_3\text{C} \equiv \text{C} - \text{CH}_3$

Solution:

$\text{Hint: Terminal alkynes are much more acidic than most other hydrocarbons.}$ $\text{Removal of the proton leads to the formation of an acetylide anion, RC} \equiv \text{C}^-.$ $\text{Explanation:}$ $\text{The higher the s-character in the hybridization of carbon, the higher is the acidity.}$ $\text{Terminal alkynes hydrogen is acidic in nature}$ $\text{because sp carbon stabilized the negative charge more effectively.}$ $\text{In the presence of a strong base, terminal alkyne loses its acidic hydrogen.}$ $\text{Among all the given options, propyne is the most acidic compound because}$ $\text{it has terminal triple bond.}$

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Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}