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Current Question (ID: 17632)

Question:

$\text{HCl with an alkene X reacts in accordance with Markovnikov's rule to give 1-Chloro-1-methylcyclohexane. The structure of alkene (X) is:}$

Options:

1. $\text{Option 1: CH}_2\text{=CH-CH}_2\text{-CH}_2\text{-CH}_2\text{-CH}_3$
2. $\text{Option 2: CH}_3\text{-CH=CH-CH}_2\text{-CH}_2\text{-CH}_3$
3. $\text{Option 3: (1) and (2)}$
4. $\text{Option 4: CH}_3\text{-CH}_2\text{-CH=CH-CH}_2\text{-CH}_3$

Solution:

$\text{Hint: Cl is attached to more substituted carbon of double bond.}$ $\text{In Markovnikov addition, more stable carbocation is formed followed by attack of nucleophile (here Cl}^-\text{).}$ $\text{In structure A, following mechanism takes place.}$ $\text{In structure B, rearrangement of carbocation occurs because 3}^\circ\text{ carbocation is more stable than 2}^\circ\text{ carbocation which ultimately gives the desired product as shown below.}$ $\text{Hence, option third is the correct answer.}$

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Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}