Import Question JSON

Current Question (ID: 17635)

Question:

$\text{The main product of the following reaction will be-}$ $\text{OH} \quad \text{CH-CH}_3 \xrightarrow{\text{conc. H}_2\text{SO}_4} \text{Product}$

Options:

1. $\text{H}_2\text{C}=\text{CH-CH}_3$
2. $\text{H}_2\text{C}=\text{CH}_2$
3. $\text{H}_3\text{C-CH}=\text{CH}_2$
4. $\text{H}_2\text{C}=\text{CH}_2$

Solution:

$\text{Hint: Rearrangement of carbocation takes place.}$ $\text{Step 1:}$ $\text{When alcohol reacts with conc. H}_2\text{SO}_4 \text{ then dehydration reaction occurs in which an alkene is obtained as a product.}$ $\text{Step 2:}$ $\text{The mechanism of the reaction is as follows:}$

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}