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Current Question (ID: 17636)

Question:
$\text{Which is the most suitable reagent among the following to distinguish compound (III) from rest of the compounds?}$ $\text{I. CH}_3 - \text{C} \equiv \text{C} - \text{CH}_3$ $\text{II. CH}_3 - \text{CH}_2 - \text{CH}_2 - \text{CH}_3$ $\text{III. CH}_3 - \text{CH}_2 - \text{C} \equiv \text{CH}$ $\text{IV. CH}_3 - \text{CH} = \text{CH}_2$
Options:
  • 1. $\text{Br}_2/\text{CCl}_4$
  • 2. $\text{Br}_2/\text{CH}_3\text{COOH}$
  • 3. $\text{Alk. KMnO}_4$
  • 4. $\text{Ammoniacal AgNO}_3$
Solution:
$\text{Hint: Ethyne has acidic hydrogen}$ $\text{It may be noted that only the terminal alkynes react with ammoniacal silver nitrate.}$ $\text{Therefore, this reaction can be used to distinguish between 1-alkynes and others such as alkane, alkenes and non-terminal alkynes.}$ $\text{CH}_3 - \text{CH}_2 - \text{C} \equiv \text{CH} + 2[\text{Ag} (\text{NH}_3)_2]\text{NO}_3 \rightarrow$ $\text{CH}_3\text{CH}_2\text{C} \equiv \text{CAg} \downarrow$ $\text{White ppt.}$

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Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}