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Current Question (ID: 17638)

Question:

$\text{The reaction of } \text{C}_6\text{H}_5\text{CH} = \text{CHCH}_3 \text{ with HBr produces:}$

Options:

1. $\text{C}_6\text{H}_5\text{CHCH}_2\text{CH}_3 \quad \begin{array}{c} \text{Br} \end{array}$
2. $\text{C}_6\text{H}_5\text{CH}_2\text{CHCH}_3 \quad \begin{array}{c} \text{Br} \end{array}$
3. $\text{C}_6\text{H}_5\text{CH}_2\text{CH}_2\text{CH}_2\text{Br}$
4. $\begin{array}{c} \text{Br} \end{array} \quad \text{C}_6\text{H}_5\text{CH} = \text{CH} - \text{CH}_3$

Solution:

$\text{Hint: Benzylic carbocation is highly stable}$ $\text{It is an example of electrophilic addition reaction where proton addition}$ $\text{takes place across the double bond resulting in more stable carbocation}$ $\text{formation and subsequent addition of nucleophile to form addition product}$ $\text{as shown below.}$ $\text{C}_6\text{H}_5\text{CH} = \text{CHCH}_3 + \text{H}^+ \rightarrow \text{C}_6\text{H}_5 - \text{CH} - \text{CH}_2 - \text{CH}_3$ $\text{Stable carbocation}$ $\text{C}_6\text{H}_5 - \text{CH} - \text{CH}_2 - \text{CH}_3 + \text{Br}^- \rightarrow \text{C}_6\text{H}_5 - \text{CH} - \text{CH}_2 - \text{CH}_3 \quad \begin{array}{c} \text{Br} \end{array}$ $\text{Addition product}$

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Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}