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Current Question (ID: 17667)

Question:
$\text{The molecule among the following that has the hybridization}$ $\text{sp}^2, \text{sp}^2, \text{sp}, \text{and sp from left to right atoms is:}$
Options:
  • 1. $\text{HC} \equiv \text{C} - \text{C} \equiv \text{H}$
  • 2. $\text{CH}_2 = \text{CH} - \text{C} \equiv \text{CH}$
  • 3. $\text{CH}_2 = \text{CH} - \text{CH} = \text{CH}_2$
  • 4. $\text{CH}_2 - \text{CH} = \text{CH} - \text{CH}_3$
Solution:
$\text{Hint: Triple bond carbon is sp and double bond carbon is sp}^2$ $\text{From left to right, the first and second carbon atoms are double bond carbon atoms hence hybridization is sp}^2,$ $\text{and the third and fourth carbon atom is triple bond carbon atoms, hence, the hybridization is sp.}$ $\text{The correct structure is as follows:}$ $\text{CH}_2^{\text{sp}^2} = \text{CH}^{\text{sp}^2} - \text{C}^{\text{sp}} \equiv \text{C}^{\text{sp}} - \text{H}$

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Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}