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Current Question (ID: 17675)

Question:
$\text{Which of the following compounds is non-aromatic?}$
Options:
  • 1. $\text{Compound 1}$
  • 2. $\text{Compound 2}$
  • 3. $\text{Compound 3}$
  • 4. $\text{Compound 4}$
Solution:
$\text{Hint: Aromatic compound is planar and follows Huckel's rule.}$ $\text{When deciding if a compound is aromatic, go through the following checklist.}$ $\text{If the compound does not meet all the following criteria, it is likely not aromatic.}$ $1. \text{The molecule is cyclic (a ring of atoms).}$ $2. \text{The molecule is planar (all atoms in the molecule lie in the same plane).}$ $3. \text{The molecule is fully conjugated (p orbitals at every atom in the ring).}$ $4. \text{The molecule has } (4n) + 2\pi \text{ electrons (n= 0 or any positive integer).}$ $\text{The compound is not aromatic as follows:}$ $\text{The above compound is anti-aromatic because it doesn't follow the Huckel's rule}$ $\text{Hückel's Rule: For a molecule to be aromatic, it must have } 4n + 2 \text{ } \pi \text{-electrons, where n is a non-negative integer (0, 1, 2, ...).}$ $\text{The cyclopentadienyl cation has one electron to form the cation, which fits the } 4n \text{ rule rather than } 4n + 2, \text{ which means it has 4 } \pi \text{-electrons.}$ $\text{Anti-Aromaticity: When a molecule has } 4n \text{ } \pi \text{-electrons, it tends to be less stable due to electron delocalization causing instability.}$

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Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}