Import Question JSON

Current Question (ID: 17831)

Question:

$\text{The incorrect statement about carbon monoxide is-}$ $1.\ \text{It reduces the oxygen-carrying ability of blood.}$ $2.\ \text{The carboxyhaemoglobin (haemoglobin bound to CO) is less stable than oxyhaemoglobin.}$ $3.\ \text{It is produced due to incomplete combustion.}$ $4.\ \text{It forms carboxyhaemoglobin.}$

Options:

1. $\text{It reduces the oxygen-carrying ability of blood.}$
2. $\text{The carboxyhaemoglobin (haemoglobin bound to CO) is less stable than oxyhaemoglobin.}$
3. $\text{It is produced due to incomplete combustion.}$
4. $\text{It forms carboxyhaemoglobin.}$

Solution:

$\text{CO binds to haemoglobin to form carboxyhaemoglobin, which is about 300 times more stable than the oxygen-haemoglobin complex.}$ $\text{Carbon monoxide causes cellular hypoxia by reducing oxygen carrying capacity and oxygen delivery to tissues, and it may also affect intracellular oxygen utilization.}$ $\text{Carbon monoxide is produced by the incomplete combustion of carbon-containing fuels, such as gas (domestic or bottled), coal, oil, coke and wood.}$ $\text{Gas stoves, fires, heating boilers, gas-powered water heaters, paraffin heaters, and solid fuel-powered water heaters are all potential sources of carbon monoxide.}$

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}