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Current Question (ID: 17832)

Question:
$\text{A factory was started near a village. Suddenly villagers started feeling the presence of irritating vapors in the village and cases of headache, chest pain, cough, dryness of throat, and breathing problems increased. Villagers blamed the emissions from the chimney of the factory for such problems. This is:}$
Options:
  • 1. $\text{Due to the burning of fossil fuels such as gasoline, coal, natural gas, etc.}$
  • 2. $\text{Due to the burning of toxic soil.}$
  • 3. $\text{Due to the burning of white Phosphorus in soil.}$
  • 4. $\text{Due to Excessive sound pollution.}$
Solution:
$\text{HINT: This is due to burning of fossil fuels.}$ $\text{Explanation:}$ $\text{The symptoms observed in the village indicate that nitrogen oxide and sulphur oxide are released from the chimney of the factory.}$ $\text{These are produced by the burning of fossil fuels such as gasoline, coal, natural gas, etc.}$ $\text{In an automobile engine, at high temperature when fossil fuel is burnt, dinitrogen and dioxygen combine to yield NO is i.e., nitric oxide.}$ $\text{N}_2 + \text{O}_2 \xrightarrow{1200-1500^\circ \text{C}} 2\text{NO}$ $2\text{NO} + \text{O}_2 \xrightarrow{1100^\circ \text{C}} 2\text{NO}_2$ $\text{SO}_2 \text{ is produced by burning of sulphur containing fossil fuel or by roasting of sulphide ores such as iron pyrites, copper pyrites, etc.}$ $\text{Cu}_2\text{S} + \text{O}_2 \rightarrow 2\text{Cu} + \text{SO}_2$

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Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}