Import Question JSON

Current Question (ID: 17834)

Question:

$\text{Consequence(s) of ozone hole is/are:}$

Options:

1. $\text{They cause death of many phytoplanktons.}$
2. $\text{Excess exposure may even cause mutation in plants.}$
3. $\text{It leads to the ageing of skin, cataracts, skin cancer, and sunburns.}$
4. $\text{All of the above.}$

Solution:

$\text{HINT: The ozone layer protects the Earth from the harmful UV radiation of the sun.}$ $\text{Explanation:}$ $\text{STEP 1:}$ $\text{In Polar regions, stratospheric clouds provide the surface for chlorine nitrate and hypochlorous acid, which react further to give molecular chlorine.}$ $\text{Molecular chlorine and HOCl are photolyzed to give chlorine-free radicals. The chlorine-free radical is continuously regenerated, thereby depleting the ozone layer.}$ $\text{This phenomenon is known as the as ‘ozone hole’.}$ $\text{STEP 2:}$ $\text{With the depletion of the layer, more radiation will enter the Earth’s atmosphere. UV radiations are harmful because they lead to the aging of the skin, cataracts, skin cancer, and sunburns.}$ $\text{They cause the death of many phytoplanktons, which leads to a decrease in fish productivity. Excess exposure may even cause mutation in plants.}$ $\text{An increase in UV radiations decreases the moisture content of the soil and damages both plants and fibers.}$

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}