Import Question JSON

Current Question (ID: 17842)

Question:
$\text{An incorrect statement regarding acid rain is that:}$ $1. \text{ It is formed due to the reaction of } \text{SO}_2 \text{ and } \text{NO}_2 \text{ with rainwater.}$ $2. \text{ It causes no damage to monuments like the Taj Mahal.}$ $3. \text{ It is harmful to plants.}$ $4. \text{ Its pH is less than 5.6}$
Options:
  • 1. $\text{It is formed due to the reaction of } \text{SO}_2 \text{ and } \text{NO}_2 \text{ with rainwater.}$
  • 2. $\text{It causes no damage to monuments like the Taj Mahal.}$
  • 3. $\text{It is harmful to plants.}$
  • 4. $\text{Its pH is less than 5.6}$
Solution:
$\text{HINT: } \text{SO}_2 \text{ and } \text{NO}_2 \text{ after oxidation and reaction with water are major contributors to acid rain.}$ $\text{Explanation:}$ $\text{When } \text{SO}_2 \text{ and } \text{NO}_2 \text{ reacts with water then acid rain is formed. The reaction is as follows:}$ $2\text{SO}_2 (g) + \text{O}_2 (g) + 2\text{H}_2\text{O} (l) \rightarrow 2\text{H}_2\text{SO}_4 (aq)$ $4\text{NO}_2 (g) + \text{O}_2 (g) + 2\text{H}_2\text{O} (l) \rightarrow 4\text{HNO}_3 (aq)$ $\text{Acid rain is harmful for agriculture, trees and plants as it dissolves and washes away nutrients needed for their growth.}$ $\text{Acid rain damages buildings and other structures made of stone or metal. The Taj Mahal in India has been affected by acid rain.}$

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Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}