Import Question JSON

Current Question (ID: 17843)

Question:

$\text{Match the terms given in Column I with the compounds given in Column II.}$ $\text{Column I}$ \quad \text{Column II}$ $\text{A. Acid rain} \quad 1. \text{CHCl}_2 - \text{CHF}_2$ $\text{B. Photochemical smog} \quad 2. \text{CO}$ $\text{C. Combination with hemoglobin} \quad 3. \text{Unsaturated hydrocarbons}$ $\text{D. Depletion of the ozone layer} \quad 4. \text{SO}_2$ $\text{Codes}$

Options:

1. $1. \ 4 \ 2 \ 3 \ 1$
2. $2. \ 1 \ 2 \ 3 \ 4$
3. $3. \ 4 \ 3 \ 2 \ 1$
4. $4. \ 4 \ 1 \ 3 \ 2$

Solution:

$\text{HINT: When chlorine and bromine atoms come into contact with ozone in the stratosphere, they destroy ozone molecules.}$ $\text{Explanation:}$ $\text{A. Acid rain is formed when sulfur dioxide (SO}_2\text{) and nitrogen oxides (NO}_x\text{) are emitted into the atmosphere and transported by wind and air currents.}$ $\text{B. Photochemical smog is formed by unburnt fuel (unsaturated hydrocarbon).}$ $\text{C. Carbon monoxide and hemoglobin is poisonous because CO combines with hemoglobin and forms a stable complex. Due to complex formation hemoglobin is unable to form a complex with oxygen.}$ $\text{D. Chlorofluorocarbon (CHCl}_2 - \text{CHF}_2\text{) cause ozone depletion.}$

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}