Import Question JSON

Current Question (ID: 17845)

Question:

$\text{When rain is accompanied by a thunderstorm, the pH value of the collected rain water is:}$ $1. \text{ Dependent upon the amount of dust in the air.}$ $2. \text{ Slightly lower when rainwater is without a thunderstorm.}$ $3. \text{ Slightly higher when the thunderstorm is not there.}$ $4. \text{ Unaffected by the occurrence of thunderstorms.}$

Options:

1. $\text{Dependent upon the amount of dust in the air.}$
2. $\text{Slightly lower when rainwater is without a thunderstorm.}$
3. $\text{Slightly higher when the thunderstorm is not there.}$
4. $\text{Unaffected by the occurrence of thunderstorms.}$

Solution:

$\text{HINT: pH value is slightly lower than without thunderstorm.}$ $\text{Explanation:}$ $\text{Thunderstorm produces acidic oxides of N, S which produces acidic rain on dissolution with water.}$ $\text{The oxides are } \text{NO}_2, \text{NO}, \text{SO}_2, \text{SO}_3 \text{ etc.}$ $\text{This can be illustrated from the following reactions:}$ $\text{SO}_3 + \text{H}_2\text{O} \rightarrow \text{H}_2\text{SO}_4$ $2 \text{NO}_2 + \text{H}_2\text{O} + [\text{O}] \rightarrow 2 \text{HNO}_3$ $\text{Since acidic mixture is formed, the pH of the resulting solution decreases and is less than rain water.}$

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}