Import Question JSON

Current Question (ID: 17847)

Question:

$\text{Statues and monuments in India are affected by acid rain because of the formation of:}$

Options:

1. $\text{CaSO}_4 \text{ on the reaction of acid rain with limestone.}$
2. $\text{CaCO}_3 \text{ on the reaction of acid rain with limestone.}$
3. $\text{Ca(HCO}_3)_2 \text{ on the reaction of acid rain with limestone.}$
4. $\text{None of the above.}$

Solution:

$\text{HINT: Acid rain contains sulphuric acid and nitric acid.}$ $\text{STEP 1: Acid rain is a byproduct of various human activities that leads to the emission of oxides of sulphur and nitrogen in the atmosphere.}$ $\text{These oxides undergo oxidation and then react with water vapour to form acids.}$ $2\text{SO}_2(g) + \text{O}_2(g) + 2\text{H}_2\text{O}(l) \rightarrow 2\text{H}_2\text{SO}_4(aq)$ $4\text{NO}_2(g) + \text{O}_2(g) + 2\text{H}_2\text{O}(l) \rightarrow 4\text{HNO}_3(aq)$ $\text{STEP 2: Acid rain causes damage to buildings and structures made of stone and metal. In India, limestone is a major stone used in the construction of various monuments and statues, including the Taj Mahal.}$ $\text{Acid rain reacts with limestone as:}$ $\text{CaCO}_3 + \text{H}_2\text{SO}_4 \rightarrow \text{CaSO}_4 + \text{H}_2\text{O} + \text{CO}_2$ $\text{This results in the loss of luster and color of monuments, leading to their disfiguration.}$

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}