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Question:
$\text{Green plants use carbon dioxide for photosynthesis and return oxygen to the atmosphere. Even then carbon dioxide is considered to be responsible for greenhouse effect:}$ $1. \text{ Due to an increase in atmospheric temperature.}$ $2. \text{ Due to ozone depletion.}$ $3. \text{ Due to decrease in atmospheric temperature.}$ $4. \text{ Due to an increase in chlorophyll concentration.}$
Options:
  • 1. $\text{Due to an increase in atmospheric temperature.}$
  • 2. $\text{Due to ozone depletion.}$
  • 3. $\text{Due to decrease in atmospheric temperature.}$
  • 4. $\text{Due to an increase in chlorophyll concentration.}$
Solution:
$\text{HINT : CO}_2 \text{ increases atmospheric temperature.}$ $\text{Explanation:}$ $\text{CO}_2 \text{ forms about 0.033 \% by volume of atmosphere. It helps to maintain the temperature of the earth required for living organisms.}$ $\text{A balance of CO}_2 \text{ is maintained in air because CO}_2 \text{ is produced from respiration, burning of fossil fuels and decomposition of limestone but at the same time, it is consumed in photosynthesis by plants.}$ $\text{However, human activities have disturbed this balance and CO}_2 \text{ level in atmosphere is in increasing order. This has happened due to deforestation, burning of more fossil fuel and industrialisation.}$ $\text{It has been estimated that CO}_2 \text{ concentration has risen about 25\% in the past century.}$ $\text{During the past nearly 120 years, the average temperature of the planet has increased by somewhere between 0.4}^\circ\text{C to 0.8}^\circ\text{C.}$ $\text{Current estimated are that doubling the CO}_2 \text{ concentration will result in a temperature increase of between 1.0}^\circ\text{C and 3.5}^\circ\text{C.}$ $\text{In greenhouse effect, contribution of CO}_2 \text{ is 50\% and of other trace gases is also about 50\%.}$

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Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}