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Current Question (ID: 17856)

Question:
$\text{CO gas is more dangerous than CO}_2 \text{ gas because:}$ $1. \text{CO is capable of forming a complex with haemoglobin (carboxyhemoglobin), that is more stable than the oxygen-haemoglobin complex.}$ $2. \text{CO is capable of forming a complex with haemoglobin (carboxyhemoglobin), that is less stable than the oxygen-haemoglobin complex.}$ $3. \text{CO}_2 \text{ is capable of forming a complex with haemoglobin (carboxyhemoglobin), that is more stable than the oxygen-haemoglobin complex.}$ $4. \text{CO}_2 \text{ is capable of forming a complex with haemoglobin (carboxyhemoglobin), that is less stable than the oxygen-haemoglobin complex.}$
Options:
  • 1. $\text{CO is capable of forming a complex with haemoglobin (carboxyhemoglobin), that is more stable than the oxygen-haemoglobin complex.}$
  • 2. $\text{CO is capable of forming a complex with haemoglobin (carboxyhemoglobin), that is less stable than the oxygen-haemoglobin complex.}$
  • 3. $\text{CO}_2 \text{ is capable of forming a complex with haemoglobin (carboxyhemoglobin), that is more stable than the oxygen-haemoglobin complex.}$
  • 4. $\text{CO}_2 \text{ is capable of forming a complex with haemoglobin (carboxyhemoglobin), that is less stable than the oxygen-haemoglobin complex.}$
Solution:
$\text{Carbon monoxide is poisonous because it is capable of forming a complex with hemoglobin (carboxyhemoglobin), which is more stable than the oxygen-hemoglobin complex.}$ $\text{The concentration range of 3\text{--}4\% of carboxyhemoglobin decreases the oxygen-carrying capacity of the blood.}$ $\text{This results in headaches, weak eyesight, nervousness, and cardiovascular disorders.}$ $\text{A more increased concentration may even lead to death. Carbon dioxide is not poisonous. It proves harmful only at very high concentrations.}$

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Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}