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Current Question (ID: 17875)

Question:
$\text{B.O.D is connected with-}$ $1. \text{Organic matter}$ $2. \text{Microbes}$ $3. \text{Both (1) and (2)}$ $4. \text{None of the above.}$
Options:
  • 1. $\text{Organic matter}$
  • 2. $\text{Microbes}$
  • 3. $\text{Both (1) and (2)}$
  • 4. $\text{None of the above.}$
Solution:
$\text{HINT: The amount of oxygen consumed by bacteria and other microorganisms while they decompose organic matter.}$ $\text{Explanation:}$ $\text{Step 1:}$ $\text{BOD refers to the biological oxygen demand by the microbes to decompose the organic matter present in the water body. Oxygen enters the water through diffusion and water has the highest potential to hold oxygen.}$ $\text{The high temperature, untreated sewage having biotoxins, hazardous waste can reduce the oxygen to an alarming level leading to the hypoxia in fishes, whereafter enduring at the maximum level they die resultantly.}$ $\text{This occurs because the untreated sewage is rich in organic matter and microbes utilize the dissolved oxygen for the decomposition.}$ $\text{Step 2:}$ $\text{Hence, BOD is connected with both Organic matter and microbes.}$

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Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}