Import Question JSON

Current Question (ID: 17876)

Question:

$\text{Incorrect statement among the following is:}$ $1.\ \text{Oxides of sulphur, nitrogen, and carbon are the most widespread air pollutant.}$ $2.\ \text{pH of drinking water should be between 6.5 and 8.5.}$ $3.\ \text{Concentration of dissolved oxygen below 6 ppm is good for the growth of fish.}$ $4.\ \text{Clean water would have a BOD value of less than 5 ppm.}$

Options:

1. $\text{Oxides of sulphur, nitrogen, and carbon are the most widespread air pollutant.}$
2. $\text{pH of drinking water should be between 6.5 and 8.5.}$
3. $\text{Concentration of dissolved oxygen below 6 ppm is good for the growth of fish.}$
4. $\text{Clean water would have a BOD value of less than 5 ppm.}$

Solution:

$\text{HINT: Minimum concentration of dissolved oxygen for growth of fish is 4-5 ppm}$ $\text{Explanation:}$ $1.)\ \text{The five primary air pollutants include carbon monoxide, nitrogen oxides, particulate matter, sulfur oxides, and volatile organic compounds. The sources for all five of these pollutants include electricity production, industry, and transportation.}$ $2.)\ \text{The pH of most drinking-water lies within the range 6.5–8.5. Natural waters can be of lower pH, as a result of, for example, acid rain or higher pH in limestone areas.}$ $3.)\ \text{If the concentration of dissolved oxygen of water is below 6 ppm then the growth of fish gets inhibited.}$ $4.)\ \text{The biochemical oxygen demand (BOD) represents the amount of dissolved oxygen (DO) consumed by biological organisms when they decompose organic matter in water.}$ $\text{Drinking water has a BOD level of 1 - 2 ppm. When the BOD value of water is in the range 3 - 5 ppm, the water is moderately clean.}$ $\text{Polluted water has a BOD value in the range of 6 - 9 ppm. In polluted water, some organic waste is present.}$

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}