Import Question JSON

Current Question (ID: 17882)

Question:

$\text{A farmer was told that fishes were not fit for human consumption because a large amount of pesticides had accumulated in the tissues of fishes. This happens:}$ $\text{1. By the transfer of pesticides in the food chain.}$ $\text{2. By the degradation of pesticides.}$ $\text{3. By the reaction of pesticides with atmospheric oxygen.}$ $\text{4. By the reaction of pesticides with atmospheric carbon dioxide.}$

Options:

1. $\text{By the transfer of pesticides in the food chain.}$
2. $\text{By the degradation of pesticides.}$
3. $\text{By the reaction of pesticides with atmospheric oxygen.}$
4. $\text{By the reaction of pesticides with atmospheric carbon dioxide.}$

Solution:

$\text{HINT: This is because of transfer of pesticides in food chain.}$ $\text{Explanation:}$ $\text{Pesticides from soil are transferred into the crops and from the crops these are transferred into rearing fish food.}$ $\text{Pesticides entered into water through rearing fish food and finally entered into the bodies of the fishes.}$ $\text{Therefore, pesticides are transferred from lower trophic level to higher trophic level through food chain.}$ $\text{Over the time, the concentration of pesticides in fishes reach a level which causes serious metabolic and physiological disorders.}$

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}