Import Question JSON

Current Question (ID: 17909)

Question:

$\text{The similarity between metallic and ionic crystals is -}$

Options:

1. $\text{Both these crystal types are held by the electrostatic force of attraction.}$
2. $\text{Both these crystal types are held by the Van der Waal's forces of attraction.}$
3. $\text{Both these crystal types are held by hydrogen bonding.}$
4. $\text{Both these crystal types are held by covalent bonding.}$

Solution:

$\text{HINT: Metallic and ionic crystals are held by the electrostatic force of attraction.}$ $\text{Explanation:}$ $\text{STEP 1:}$ $\text{The basis of similarities between metallic and ionic crystals is that both these crystal types are held by the electrostatic force of attraction.}$ $\text{In metallic crystals, the electrostatic force acts between the positive ions and the electrons.}$ $\text{In ionic crystals, it acts between the oppositely-charged ions.}$ $\text{Hence, both have high melting points.}$ $\text{The basis of differences between metallic and ionic crystals is that in metallic crystals, the electrons are free to move and so, metallic crystals can conduct electricity.}$ $\text{However, in ionic crystals, the ions are not free to move.}$ $\text{As a result, they cannot conduct electricity.}$ $\text{However, in molten state or in aqueous solution, they do conduct electricity.}$ $\text{STEP 2:}$ $\text{The constituent particles of ionic crystals are ions.}$ $\text{These ions are held together in three-dimensional arrangements by the electrostatic force of attraction.}$ $\text{Since the electrostatic force of attraction is very strong, the charged ions are held in fixed positions.}$ $\text{This is the reason why ionic crystals are hard and brittle.}$

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}